x 0.8 x 0.8) x À = R. 0.184746 to. cub

6. Le tiers de la hauteur = 1.35 + 3 = 0.45 ver. La hauteur =

PROBLÈME VII, — &xERoIOES (p. 306).

1. La basc supérieure = 2.5981 x (0.20)2 = 0.103924 ver. car. La base infér. — 2.5981 x (0.702 = 1.273069) ver. car. La

moyenne des bases = (0.103924 x 1.273069) — 0.363734 ver. car. La somme des bases = 0.103924 } 1.273069 + 0.363734 = 1.740727. Le volume du tronc = (2 x 1.740727) + 3 = R. 1.160484 ver. cub.

2. 15 po. = 1£ = . = À; (= 83; (2 =1;28 x EL — #2: VH=i; (++ 8) x 8 = 41% = R. 19.5) pi. cub.

8. 11204774 x 8 = 3.8710 = surf. de la base ; 1.7204774 x 4 = 0.4301 = surf. de l’autre base; 3.8710 x 0.4301—V 1.66491710 — 1.2903, moyenne ; 1.2903 + 3.8710 + 0.4301 = 5.5914; 65.5914 X ÿ = KR. 9.319 pi. cub. É

4. 504 x 372 mn 187488 ; 4 187488 = 433; 504 + 372 + 433 — 1309; 1309 + 3 mm 4364; 314 pi. = 378 po.; 4634 x 378 = R. 164934 po. oub. = 96.44 + pi. cubes.

paoscème VIII, — :xerorces (p. 307). 6 1. 3.1416 x (10 x 2) x 60 = R. 3141.6.

2. 3.1416 x 4 x 3.75 == R. 47.1240 ver. car. L 8. 19 3.1416 x 0.35 x 2 x (0.35 x 4)= lère R. 3.078768 ver. car. ; 20 3.1416 x 0.35 x 0.35 x 2 = 2e R. 0.769692 ver. car. 9 4. 3.1416 x 30 mm 94.248505; 94.248 x 15 — 1413.72, pourtour; "

80 x 30 x 0.7854 == 706.86, plafond ; (1413.72 + 706.86) + 9 = 235.62 ver. oar. ; $2.50 x 235.62 = R. $#589.05.

5. Le rayon «= (3.08 + 3.1416) = 0.99 to.; la surf. latérale = 8.1416 x (0.99 x 2) x (0.99 x 3) = R. 18.4744 to. car,